$Ontext Design of a network of heat exchangers in parallel (with recirculation) with two hot streams and one cold stream. Floudas, C.A., Pardalos, P.M., et al. "Handbook of Test Problems in Local and Global Optimization". Kluwer Academic Publishers, Dordrecht, 1999. Section 5.4.3. Test Problem 2, pages 52-54. $Offtext Scalars Tcin inlet temperature of cold stream /150/ Tcout outlet temperature of cold stream /310/ ; Variables dT11 temperature difference at hot end of exchanger H1-C dT12 temperature difference at cold end of exchanger H1-C dT21 temperature difference at hot end of exchanger H2-C dT22 temperature difference at cold end of exchanger H2-C f11, f12, f13, f14 f21, f22, f23, f24 t1i, t2i, t1o, t2o objval objective function variable ; Free variables obj; Equations g1, g2, g3, g4, g5, g6, g7, g8, g9, g10 g11, g12, g13 f objective function ; * Objective function: f.. objval =e=1300*(1000/((1/30)*(dT11*dT12)+(1/6)*(dT11+dT12)))**0.6+ 1300*( 600/((1/30)*(dT21*dT22)+(1/6)*(dT21+dT22)))**0.6; * Constraints: g1.. f11 + f21 =e= 10; g2.. f11 + f23 - f12 =e= 0; g3.. f21 + f13 - f22 =e= 0; g4.. f14 + f13 - f12 =e= 0; g5.. f24 + f23 - f22 =e= 0; g6.. Tcin*f11 + t2o*f23 - t1i*f12 =e= 0; g7.. Tcin*f21 + t1o*f13 - t2i*f22 =e= 0; g8.. f12*(t1o - t1i) =e= 1000; g9.. f22*(t2o - t2i) =e= 600; g10.. dT11 + t1o =e= 500; g11.. dT12 + t1i =e= 250; g12.. dT21 + t2o =e= 350; g13.. dT22 + t2i =e= 200; * Bounds on variables: dT11.lo = 10; dT11.up = 350; dT12.lo = 10; dT12.up = 350; dT21.lo = 10; dT21.up = 200; dT22.lo = 10; dT22.up = 200; f11.lo = 0; f11.up = 10; f12.lo = 0; f12.up = 10; f13.lo = 0; f13.up = 10; f14.lo = 0; f14.up = 10; f21.lo = 0; f21.up = 10; f22.lo = 0; f22.up = 10; f23.lo = 0; f23.up = 10; f24.lo = 0; f24.up = 10; t1i.lo = 150; t1i.up = Tcout; t1o.lo = 150; t1o.up = Tcout; t2i.lo = 150; t2i.up = Tcout; t2o.lo = 150; t2o.up = Tcout; * Initial point: dT11.l = 200; dT12.l = 50; dT21.l = 150; dT22.l = 50; f11.l = 10; f12.l = 10; f13.l = 10; f14.l = 10; f21.l = 10; f22.l = 10; f23.l = 10; f24.l = 10; t1i.l = 200; t1o.l = 100; t2i.l = 300; t2o.l = 200; MODEL HeatEx3 /ALL/; SOLVE HeatEx3 USING NLP MINIMIZING objval; * End HeatEx3