feasopt1.gms : An Infeasible Transportation Problem analyzed with Cplex option FeasOpt
This problem finds a least cost shipping schedule that meets
requirements at markets and supplies at factories where demand
exceeds supply using the Cplex feature FeasOpt.
Reference:
- Dantzig, G B, Chapter 3.3. In Linear Programming and Extensions. Princeton University Press, Princeton, New Jersey, 1963.
Small Model of Type: LP
$Title An Infeasible Transportation Problem analyzed with Cplex option FeasOpt (FEASOPT1,SEQ=314)
$Ontext
This problem finds a least cost shipping schedule that meets
requirements at markets and supplies at factories where demand
exceeds supply using the Cplex feature FeasOpt.
Dantzig, G B, Chapter 3.3. In Linear Programming and Extensions.
Princeton University Press, Princeton, New Jersey, 1963.
$Offtext
Sets
i canning plants / seattle, san-diego /
j markets / new-york, chicago, topeka / ;
Parameters
a(i) capacity of plant i in cases
/ seattle 350
san-diego 600 /
b(j) demand at market j in cases
/ new-york 325
chicago 300
topeka 275 / ;
Table d(i,j) distance in thousands of miles
new-york chicago topeka
seattle 2.5 1.7 1.8
san-diego 2.5 1.8 1.4 ;
Scalar f freight in dollars per case per thousand miles /90/ ;
Parameter c(i,j) transport cost in thousands of dollars per case ;
c(i,j) = f * d(i,j) / 1000 ;
Variables
x(i,j) shipment quantities in cases
z total transportation costs in thousands of dollars ;
Positive Variable x ;
Equations
cost define objective function
supply(i) observe supply limit at plant i
demand(j) satisfy demand at market j ;
cost .. z =e= sum((i,j), c(i,j)*x(i,j)) ;
supply(i) .. sum(j, x(i,j)) =l= a(i) ;
demand(j) .. sum(i, x(i,j)) =g= b(j) ;
Model transport /all/ ; option limrow=0, limcol=0;
* Increase demand by 20%
b(j) = 1.2*b(j);
Solve transport using lp minimizing z ;
display 'The first phase of the Simplex algorithm distributed the infeasibilities as follows',
x.infeas, supply.infeas, demand.infeas;
Option lp=cplex;
file fcpx Cplex Option file / cplex.opt /; transport.optfile=1;
* Lets try to move the infeasibilities on the demand side
putclose fcpx / 'feasopt 1' / 'equation.feaspref 0' / 'demand.feaspref 1';
Solve transport using lp minimizing z ;
display 'All infeasibilities should be in the demand equations', x.infeas, supply.infeas, demand.infeas;
abort$(sum((i,j), x.infeas(i,j)) + sum(i,supply.infeas(i))) x.infeas, supply.infeas, demand.infeas;
* Lets try to distribute the infeasibilities on the demand side by
* using the sum of squares for the relaxation measurement
putclose fcpx / 'feasopt 1' / 'feasoptmode 4' / 'equation.feaspref 0' / 'demand.feaspref 1';
Solve transport using lp minimizing z ;
display 'All infeasibilities should be in the demand equations and nicely distributed',
x.infeas, supply.infeas, demand.infeas;
abort$(sum((i,j), x.infeas(i,j)) + sum(i,supply.infeas(i))) x.infeas, supply.infeas, demand.infeas;
* Lets try to distribute the infeasibilities on the demand and supply
* side by using the sum of squares for the relaxation measurement
putclose fcpx / 'feasopt 1' / 'feasoptmode 4';
Solve transport using lp minimizing z ;
display 'All infeasibilities should be in the demand and supply equations and nicely distributed',
x.infeas, supply.infeas, demand.infeas;
abort$(sum((i,j), x.infeas(i,j))) x.infeas, supply.infeas, demand.infeas;
* Lets try to distribute the infeasibilities on the demand and supply
* side by using the sum of squares for the relaxation measurement and
* lets also optimize the transport shipment with respect to the
* original objective function
putclose fcpx / 'feasopt 1' / 'feasoptmode 5';
Solve transport using lp minimizing z ;
display 'All infeasibilities should be in the demand equations and nicely distributed with an "optimal" x',
x.infeas, supply.infeas, demand.infeas, x.l;
abort$(sum((i,j), x.infeas(i,j))) x.infeas, supply.infeas, demand.infeas;
* Lets adjust supply and demands based on the relaxation found
a(i) = a(i) + supply.infeas(i);
b(j) = b(j) - demand.infeas(j);
* Now we should have a feasible model. The primals from our previous
* solve should be the optimal one, so lets save them to compare them
* with the outcome with the next solve;
Parameter xbest(i,j); xbest(i,j) = x.l(i,j);
* Lets try the 'advind 2' Cplex option to allow Cplex to do a good
* start from just the primals using primal Simplex
putclose fcpx / 'advind 2' / 'lpmethod 1';
Solve transport using lp minimizing z ;
* We better have an optimum solution and the same primals as in the
* previous run. This is a little dangerous since the problem is
* degenerated.
abort$(transport.modelstat<>1 or sum((i,j), xbest(i,j) - x.l(i,j))>1e-6) x.l, xbest;