flds911.gms : Princeton Bilevel Optimization Example 9.1.1

Description

```Test problem 9.2.2 in Handbook of Test Problems in Local and Global Optimization
Test problem 9.1.1 on http://titan.princeton.edu/TestProblems/chapter9.html

References:

Floudas, C A, Pardalos, P M, Adjiman, C S, Esposito, W R, Gumus, Z H, Harding,
S T, Klepeis, J L, Meyer, C A, and Schweiger, C A, Handbook of Test Problems in
Local and Global Optimization. Kluwer Academic Publishers, 1999

Clark, P A, and Westerberg, A W, Bilevel Programming for Steady-State Chemical
Process Design-i. Fundamentals and Algorithms. Comput. Chem. Eng. 14 (1990), 87-97.

NOTE:

The problem 9.1.1 on the web gives the solution y1=4, y2=2, and x=5.
However, the KKT condition
kt2..   4*lb('2') - 2*lb('2') - 3*lb('3')  =e= 0;
seems to be incorrect. It does not match equation c1-c3. It but should be
kt2..   4*lb('1') - 2*lb('2') - 3*lb('3')  =e= 0;
Then, the model gives the solution y1=4, y2=6, and x=6 which is
verified the EMP model below.

We did NOT verify this by checking the original reference!

Contributor: Alex Meeraus and Jan-H. Jagla, December 2009
```

Small Model of Type : BP

Category : GAMS EMP library

Main file : flds911.gms

``````\$title Princeton Bilevel Optimization Example 9.1.1 (FLDS911,SEQ=27)

\$ontext

Test problem 9.2.2 in Handbook of Test Problems in Local and Global Optimization
Test problem 9.1.1 on http://titan.princeton.edu/TestProblems/chapter9.html

References:

Floudas, C A, Pardalos, P M, Adjiman, C S, Esposito, W R, Gumus, Z H, Harding,
S T, Klepeis, J L, Meyer, C A, and Schweiger, C A, Handbook of Test Problems in
Local and Global Optimization. Kluwer Academic Publishers, 1999

Clark, P A, and Westerberg, A W, Bilevel Programming for Steady-State Chemical
Process Design-i. Fundamentals and Algorithms. Comput. Chem. Eng. 14 (1990), 87-97.

NOTE:

The problem 9.1.1 on the web gives the solution y1=4, y2=2, and x=5.
However, the KKT condition
kt2..   4*lb('2') - 2*lb('2') - 3*lb('3')  =e= 0;
seems to be incorrect. It does not match equation c1-c3. It but should be
kt2..   4*lb('1') - 2*lb('2') - 3*lb('3')  =e= 0;
Then, the model gives the solution y1=4, y2=6, and x=6 which is
verified the EMP model below.

We did NOT verify this by checking the original reference!

Contributor: Alex Meeraus and Jan-H. Jagla, December 2009

\$offtext

*Solution of problem 9.1.1 on the web
scalar  x_l /    6 /
y1_l /    4 /
y2_l /    6 /
tol / 1e-6 /;

variables z, y1, y2; positive variable x;
equations ob, c1, c2, c3, c4, c5;

ob..  -   x - 3*y1 + 2*y2 =e=   z;

c1..  - 2*x +   y1 + 4*y2 =l=  16;
c2..    8*x + 3*y1 - 2*y2 =l=  48;
c3..  - 2*x +   y1 - 3*y2 =l= -12;
c4..        -   y1        =l=   0;
c5..            y1        =l=   4;

model bilevel / all /;

\$echo bilevel x max y1 * c1 c2 c3 c4 c5 > "%emp.info%"

*Start from reported solution
x.l  = x_l ;
y1.l = y1_l;
y2.l = y2_l;

solve bilevel using EMP minimizing z;

abort\$(   (abs( x.l -  x_l) > tol)
or (abs(y1.l - y1_l) > tol)
or (abs(y2.l - y2_l) > tol) ) 'Deviated from reported solution';
``````