prodplan.gms : A Production Planning Example

**Description**

This uncapacitated lot-sizing problem finds the least cost production plan meeting demand requirements. There are costs given for producing, stocking, and setting up the machines. Four solving approaches are presented: 1) Solving the original model as a MIP 2) Solving a tight reformulation as an RMIP 3) Solving a tight reforumulation without stock as an RMIP 4) Solving the original model as an RMIP using a separation algorithm

**Reference**

- Pochet, Y, and Wolsey, L A, Production Planning by Mixed Integer Programming (Springer Series in Operations Research and Financial Engineering). Springer-Verlag New York, Inc., 2006.

**Small Model of Type :** MIP

**Category :** GAMS Model library

**Main file :** prodplan.gms

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$title A Production Planning Example (PRODPLAN, SEQ=356)
$onText
This uncapacitated lot-sizing problem finds the least cost production plan
meeting demand requirements. There are costs given for producing, stocking,
and setting up the machines.
Four solving approaches are presented:
1) Solving the original model as a MIP
2) Solving a tight reformulation as an RMIP
3) Solving a tight reforumulation without stock as an RMIP
4) Solving the original model as an RMIP using a separation algorithm
Pochet, Y, and Wolsey, L A, Production Planning by Mixed Integer
Programming (Springer Series in Operations Research and Financial
Engineering). Springer-Verlag New York, Inc., 2006.
Keywords: mixed integer linear programming, relaxed mixed integer linear
programming, production planning
$offText
*1) Initial tiny formulation
Set
t 'time periods' / t1*t8 /
ut(t,t) 'upper triangle';
Alias (t,tt,k);
Parameter
DEMAND(T) 'demand per period' / (t1,t2) 400, (t3,t4) 800, (t5*t8) 1200 /
SETUPCOST 'setup cost per period' / 5000 /
PRODCOST 'production cost per period' / 100 /
INVCOST 'production cost per period' / 5 /
STOCKINI 'production cost per period' / 200 /
BigM(T) 'max production - BigM';
*We assume that the initial stock is lower equal than the demand in the first period
abort$(Demand('t1') < STOCKINI) 'Initial stock is too large';
ut(k,t) = ord(k) <= ord(t);
BigM(t) = sum(k$(ord(k) >= ord(t)), DEMAND(k) - STOCKINI$(ord(t) = 1));
display ut, BigM;
Variable
s(t) 'inventory in period t'
x(t) 'production in period t'
y(t) 'setup in period t'
cost;
Binary Variable y;
Positive Variable s, x;
Equation
Balance(t) 'stock balance'
Production(t) 'production set-up'
Mincost 'objective function';
Mincost..
cost =e= sum(t, ifthen(ord(t) < card(t),INVCOST,INVCOST/2)*s(t)) + sum(t, SETUPCOST*y(t) + PRODCOST*x(t));
Production(t)..
x(t) =L= BigM(t)*y(t);
Balance(t)..
STOCKINI$(ord(t) = 1) + s(t-1) + x(t) =e= DEMAND(t) + s(t);
Model tiny / Mincost, Production, Balance /;
tiny.optCr=0;
solve tiny minimizing cost using mip;
*2) Multi-commodity formulation (tight reformulation)
Variable
smc(t,t) 'inventory entered in period i for period t'
xmc(t,t) 'production in period i for demand in t';
Positive Variable smc, xmc;
Equation
Balancemc(t,t) 'stock balance'
Productionmc(t,t) 'production set-up'
Mincostmc 'objective function';
Mincostmc..
cost =e= sum(ut, PRODCOST*xmc(ut) + INVCOST*smc(ut)) + sum(t, SETUPCOST*y(t));
Balancemc(ut(k,t))..
STOCKINI$(ord(t) = 1) + smc(k-1,t) + xmc(k,t) =e= smc(k,t) + diag(k,t)*DEMAND(t);
Productionmc(ut(k,t))..
xmc(k,t) =l= (DEMAND(t) - STOCKINI$(ord(t) = 1))*y(k);
Model tinymc / Mincostmc, Balancemc, Productionmc /;
solve tinymc minimizing cost using rmip;
*3) Multi-commodity formulation without stock (tight reformulation)
Parameter dist(t,t) 'distance between time periods';
dist(ut(k,t)) = ord(t) - ord(k);
display dist;
Equation
Demandmcws(t) 'demand satisfaction'
Mincostmcws 'objective function';
Mincostmcws..
cost =e= sum(ut, PRODCOST*xmc(ut) + INVCOST*dist(ut)*xmc(ut)) + sum(t, SETUPCOST*y(t));
Demandmcws(t)..
sum(ut(k,t), xmc(k,t)) =g= DEMAND(t) - STOCKINI$(ord(t) = 1);
Model tinymcws / Mincostmcws, Demandmcws, Productionmc /;
solve tinymcws minimizing cost using rmip;
*4) Separation Algorithm
Set
j 'iterations' /j1*j10/
n(j,t) 'set of cuts'
Scon(j,t,t) 'set of violated constraints';
n(j,t) = no;
Scon(j,t,t) = no;
Alias (t,l), (j,jj);
Parameter
D(t,t) 'accumulated demand'
left(t,t) 'left side of cut';
D(ut(t,k)) = sum[tt$(ord(tt) <= ord(k) and ord(tt) >= ord(t)), DEMAND(tt)];
Equation cuts(j,t) 'cuts for the RMIP (complete linear description)';
cuts(n(jj,t)).. sum(Scon(jj,t,k), x(k) - D(k,t)*y(k)) =l= s(t);
Model tinycuts / tiny, cuts /;
Scalar
more / 1 /
epsilon / 1e-6 /;
*If STOCKINI < DEMAND(t1) there has to be production in the first period
y.fx('t1') = 1;
loop(j$more,
solve tinycuts using rmip min cost;
option limCol = 0, limRow = 0, solPrint = silent;
* Store the left hand side of potential cuts
left(ut(tt,l)) = x.l(tt)-d(tt,l)*y.l(tt);
* Use only those LHS which are greater zero
Scon(j,l,tt) = left(tt,l) > epsilon;
* If the sum of those is greater than the inventory level: violation found
* Add this cut to the model
n(j,l) = sum[Scon(j,l,tt), left(tt,l)] - epsilon > s.l(l);
* Proceed if at least one cut was added during this iteration
more = sum(n(j,l), yes);
);
put_Utility$(not more) 'log' /
'>>>>Integer solution found. A total of 'sum(n(j,t),1):0:0' cuts were added.';
```